I realized that we actually don't need to have a closing bracket to signal the end of the expression. We just need to implement something like the $ operator in haskell.
def (foo a b c)
if $ and
a = 5
b = 10
c = 15
prn "success"
prn "failed"
There should be enough information based off of the indentation to tell how it should be parsed. $ should mean something along the lines of everything indented after the next symbol is a single expression.
You'll like the old discussion on Bullet which had some similar ideas, including considering how to suppress paren-insertion inside such a special operator, etc.
