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2 points by rocketnia 5112 days ago | link | parent

I thought the point of 'baz was to call the first parameter with the second parameter. That is, the result of (baz "abc" 0) would be the character #\a if not for that meddling macro. Your 'baz1 is totally different.

BTW, here's my version of 'baz: (def baz (m index) do.m.index)



1 point by evanrmurphy 5112 days ago | link

Yes, you are right. My 'baz1 doesn't work as intended.

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